Appendix B: Derivation for equations 11, 14 and 15

We first reformulate equation 10 as

$\displaystyle \mathbf{S} = \tilde{\mathbf{M}} -\mathbf{U}_1^S(\mathbf{U}_1^S)^H\mathbf{N}.$ (29)

Inserting equation 6 into equation 29, we can further derive

\begin{displaymath}\begin{split}
\mathbf{S} = \mathbf{U}_1^M\Sigma_1^M(\mathbf{V}_1^M)^H -\mathbf{U}_1^S(\mathbf{U}_1^S)^H\mathbf{N}.
\end{split}\end{displaymath} (30)

Because equations 5 and 9 are both SVDs of $\mathbf{M}$, we let

$\displaystyle \mathbf{U}_1^S=\mathbf{U}_1^M,$ (31)

and

$\displaystyle \Sigma_1=\Sigma_1^M,$ (32)

and

$\displaystyle (\mathbf{N}^H\mathbf{U}_1^S+\mathbf{V}_1^S\Sigma_1^S)(\Sigma_1)^{-1}=\mathbf{V}_1^M.$ (33)

Considering $\Sigma_1= \Sigma_1^M\mathbf{B}$,

$\displaystyle \mathbf{B}=\mathbf{I}.$ (34)

From equation 33,

\begin{displaymath}\begin{split}
\mathbf{V}_1^S&=(\mathbf{V}_1^M-\mathbf{N}^H\ma...
...a_1(\Sigma_1^S)^{-1}\\
&=\mathbf{V}_1^M\mathbf{A},
\end{split}\end{displaymath} (35)

where $(\mathbf{V}_1^M)^{o}$ satisfies that $\parallel\mathbf{I}-\mathbf{V}_1^M(\mathbf{V}_1^M)^{o} \parallel\rightarrow 0$.

Considering $\mathbf{V}_1^S=\mathbf{V}_1^M\mathbf{A}$,

\begin{displaymath}\begin{split}
\mathbf{A}&\approx (\mathbf{I}-(\mathbf{V}_1^M)...
...\\
&=(\mathbf{I}-\Gamma)\Sigma_1(\Sigma_1^S)^{-1},
\end{split}\end{displaymath} (36)

where $\Gamma=(\mathbf{V}_1^M)^{o}\mathbf{N}^H\mathbf{U}_1^S(\Sigma_1)^{-1}$.

Inserting equations 31 and 33 into equation 30, we can obtain:

\begin{displaymath}\begin{split}
\mathbf{S} &= \mathbf{U}_1^M\Sigma_1^M(\mathbf{...
...1^M)^H-\Sigma_1^S(\mathbf{V}_1^S)^H\right]\right\}.
\end{split}\end{displaymath} (37)


2020-02-21